What is the average power consumed by a 64 year old woman during the ascent of 15 cm high steps, if her mass is 54 kg?

What is the average power consumed by a 64 year old woman during the ascent of 15 cm high steps, if her mass is 54 kg?

• A. 10 W
• B. 20 W
• C. 40 W
• D. 90 W

Answer: (D)

To find the average power consumed by the woman while ascending 15 cm high steps, we need to consider the work done against gravity and the time taken for the ascent. First, we calculate the work done (W) while ascending. The work done against gravity can be expressed with the formula: \[ W = mgh \] where: - \( m \) is the mass (54 kg), - \( g \) is the acceleration due to gravity (approximately 9.81 m/s²), - \( h \) is the height gained (0.15 m, since 15 cm is converted to meters). Substituting in the values: \[ W = 54 \, \text{kg} \times 9.81 \, \text{m/s}^2 \times 0.15 \, \text{m} \] \[ W = 54 \times 9.81 \times 0.15 \] \[ W \approx 80.7 \, \text{J} \] Next, to find average power (P), we use the formula: \[ P = \frac{W}{t} \] where \( t \) is the time taken to ascend the

To find the average power consumed by the woman while ascending 15 cm high steps, we need to consider the work done against gravity and the time taken for the ascent.

First, we calculate the work done (W) while ascending. The work done against gravity can be expressed with the formula:

[ W = mgh ]

where:

• ( m ) is the mass (54 kg),

• ( g ) is the acceleration due to gravity (approximately 9.81 m/s²),

• ( h ) is the height gained (0.15 m, since 15 cm is converted to meters).

Substituting in the values:

[ W = 54 , \text{kg} \times 9.81 , \text{m/s}^2 \times 0.15 , \text{m} ]

[ W = 54 \times 9.81 \times 0.15 ]

[ W \approx 80.7 , \text{J} ]

Next, to find average power (P), we use the formula:

[ P = \frac{W}{t} ]

where ( t ) is the time taken to ascend the