What is the equivalent resistance of a 60-Ω resistor connected in parallel with a 20-Ω resistor?

What is the equivalent resistance of a 60-Ω resistor connected in parallel with a 20-Ω resistor?

• A. 80 Ω
• B. 40 Ω
• C. 15 Ω
• D. 3 Ω

Answer: (C)

To find the equivalent resistance of resistors connected in parallel, you can use the formula: \[ \frac{1}{R_{\text{eq}}} = \frac{1}{R_1} + \frac{1}{R_2} \] In this case, the two resistors are 60 Ω and 20 Ω. Substituting the values into the formula gives: \[ \frac{1}{R_{\text{eq}}} = \frac{1}{60} + \frac{1}{20} \] To add these fractions, it can be helpful to find a common denominator. The least common multiple of 60 and 20 is 60. Thus, we rewrite the second fraction: \[ \frac{1}{20} = \frac{3}{60} \] Now we can combine the fractions: \[ \frac{1}{R_{\text{eq}}} = \frac{1}{60} + \frac{3}{60} = \frac{4}{60} \] This simplifies to: \[ \frac{1}{R_{\text{eq}}} = \frac{1}{15} \] To find \(R_{\text

To find the equivalent resistance of resistors connected in parallel, you can use the formula:

[

\frac{1}{R_{\text{eq}}} = \frac{1}{R_1} + \frac{1}{R_2}

]

In this case, the two resistors are 60 Ω and 20 Ω. Substituting the values into the formula gives:

[

\frac{1}{R_{\text{eq}}} = \frac{1}{60} + \frac{1}{20}

]

To add these fractions, it can be helpful to find a common denominator. The least common multiple of 60 and 20 is 60. Thus, we rewrite the second fraction:

[

\frac{1}{20} = \frac{3}{60}

]

Now we can combine the fractions:

[

\frac{1}{R_{\text{eq}}} = \frac{1}{60} + \frac{3}{60} = \frac{4}{60}

]

This simplifies to:

[

\frac{1}{R_{\text{eq}}} = \frac{1}{15}

]

To find (R_{\text